x^2-22x-9x^2=0

Solution for x^2-22x-9x^2=0 equation:

x^2-22x-9x^2=0

We add all the numbers together, and all the variables

-8x^2-22x=0

a = -8; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·(-8)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*-8}=\frac{0}{-16}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*-8}=\frac{44}{-16}
=-2+3/4
$